What is expand (e^{2x}-1)(e^{2x}+1) ?

The solution to expand (e^{2x}-1)(e^{2x}+1) is e^{4x}-1

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expand (e^{2x}-1)(e^{2x}+1)

expand

(e^{2 x} - 1) (e^{2 x} + 1)

e^{4 x} - 1

Solution steps

(e^{2 x} - 1) (e^{2 x} + 1)

Apply Difference of Two Squares Formula:

(a - b) (a + b) = a^{2} - b^{2}

a = e^{2 x}, b = 1

= (e^{2 x})^{2} - 1^{2}

Simplify

(e^{2 x})^{2} - 1^{2} : e^{4 x} - 1

= e^{4 x} - 1

(- 12 mn + 5) l e f t (- 3 mn - 2)

(a - 3 x - 2) x (a + 3 x - 2)

\frac{x ^{2} + 6}{2 x + 1} - \frac{1}{2} x

12 (1 - \frac{0.87}{π})

(x - 1 - 1) (x - 1 + 1)

What is expand (e^{2x}-1)(e^{2x}+1) ?
The solution to expand (e^{2x}-1)(e^{2x}+1) is e^{4x}-1