What is expand (x^3+3x-2x^2-6)+i(-2x^2+4x) ?

The solution to expand (x^3+3x-2x^2-6)+i(-2x^2+4x) is (x^3+3x-2x^2-6)+(-2x^2+4x)i

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expand (x^3+3x-2x^2-6)+i(-2x^2+4x)

expand

(x^{3} + 3 x - 2 x^{2} - 6) + i (- 2 x^{2} + 4 x)

(x^{3} + 3 x - 2 x^{2} - 6) + (- 2 x^{2} + 4 x) i

Solution steps

(x^{3} + 3 x - 2 x^{2} - 6) + i (- 2 x^{2} + 4 x)

Apply rule:

(a) = a

(x^{3} + 3 x - 2 x^{2} - 6) = x^{3} + 3 x - 2 x^{2} - 6

= x^{3} + 3 x - 2 x^{2} - 6 + i (- 2 x^{2} + 4 x)

Expand

i (- 2 x^{2} + 4 x) : - 2 x^{2} i + 4 x i

= x^{3} + 3 x - 2 x^{2} - 6 - 2 x^{2} i + 4 x i

Rewrite in standard complex form:

(x^{3} + 3 x - 2 x^{2} - 6) + (- 2 x^{2} + 4 x) i

= (x^{3} + 3 x - 2 x^{2} - 6) + (- 2 x^{2} + 4 x) i

in (\frac{e x ^{2}}{y})

(\frac{1}{x} + y) (\frac{1}{x} - y)

(e^{x i} - cos (x))^{2}

(\frac{6}{7} - x)^{5}

\frac{\partial}{\partial x} ((x) (x - 3) (y - 4))

What is expand (x^3+3x-2x^2-6)+i(-2x^2+4x) ?
The solution to expand (x^3+3x-2x^2-6)+i(-2x^2+4x) is (x^3+3x-2x^2-6)+(-2x^2+4x)i