What is expand (tan((180-θ)/2)(t-2w))/(2) ?

The solution to expand (tan((180-θ)/2)(t-2w))/(2) is (ttan((180-θ)/2))/(2)-wtan((-θ+180)/2)

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expand (tan((180-θ)/2)(t-2w))/(2)

expand

\frac{tan ( \frac{180 - θ}{2} ) ( t - 2 w )}{2}

\frac{t tan ( \frac{180 - θ}{2} )}{2} - w tan (\frac{- θ + 180}{2})

Solution steps

\frac{tan ( \frac{180 - θ}{2} ) ( t - 2 w )}{2}

Expand

tan (\frac{180 - θ}{2}) (t - 2 w) : t tan (\frac{180 - θ}{2}) - 2 w tan (\frac{180 - θ}{2})

= \frac{t tan ( \frac{- θ + 180}{2} ) - 2 w tan ( \frac{- θ + 180}{2} )}{2}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{t tan ( \frac{180 - θ}{2} ) - 2 w tan ( \frac{180 - θ}{2} )}{2} = \frac{t tan ( \frac{180 - θ}{2} )}{2} - \frac{2 w tan ( \frac{180 - θ}{2} )}{2}

= \frac{t tan ( \frac{- θ + 180}{2} )}{2} - \frac{2 w tan ( \frac{- θ + 180}{2} )}{2}

Divide the numbers:

\frac{2}{2} = 1

= \frac{t tan ( \frac{- θ + 180}{2} )}{2} - w tan (\frac{- θ + 180}{2})

(1 - cos (x)) (x - sin (x))

\frac{2 x ^{3} - 36 x ^{2} + 432 x - 3240}{x ( x - 12 )}

\frac{4 s - 10}{( s - 3 ) ( s - 2 ) ( s - 1 )}

P (x, y) A (- 5, - 4) B (3, 18)

- 9 (x + Δ x)^{2} - 15

What is expand (tan((180-θ)/2)(t-2w))/(2) ?
The solution to expand (tan((180-θ)/2)(t-2w))/(2) is (ttan((180-θ)/2))/(2)-wtan((-θ+180)/2)