What is expand ((2x-1)^2)/(2x) ?

The solution to expand ((2x-1)^2)/(2x) is 2x-2+1/(2x)

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expand ((2x-1)^2)/(2x)

expand

\frac{( 2 x - 1 ) ^{2}}{2 x}

2 x - 2 + \frac{1}{2 x}

Solution steps

\frac{( 2 x - 1 ) ^{2}}{2 x}

(2 x - 1)^{2} = 4 x^{2} - 4 x + 1

= \frac{4 x ^{2} - 4 x + 1}{2 x}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{4 x ^{2} - 4 x + 1}{2 x} = \frac{4 x ^{2}}{2 x} - \frac{4 x}{2 x} + \frac{1}{2 x}

= \frac{4 x ^{2}}{2 x} - \frac{4 x}{2 x} + \frac{1}{2 x}

Cancel

\frac{4 x ^{2}}{2 x} : 2 x

= 2 x - \frac{4 x}{2 x} + \frac{1}{2 x}

Cancel

\frac{4 x}{2 x} : 2

= 2 x - 2 + \frac{1}{2 x}

\frac{( s - s e ^{- 4 s} - 10 )}{( s ^{2} \cdot ( s ^{2} + 2 s ) )}

- (z^{2} + 1) (x d z - z d x)

- \frac{5}{( 2 x - 1 ) ^{2}}

(5 x - 1 + x + 3)^{2}

\frac{( p - q ) ^{2}}{p + q}

What is expand ((2x-1)^2)/(2x) ?
The solution to expand ((2x-1)^2)/(2x) is 2x-2+1/(2x)