What is expand-(sin(x))/(ln(2(cos(x)+ln(pi)))) ?

The solution to expand-(sin(x))/(ln(2(cos(x)+ln(pi)))) is -(sin(x))/(ln(2cos(x)+2ln(pi)))

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expand-(sin(x))/(ln(2(cos(x)+ln(pi))))

expand

- \frac{sin ( x )}{ln ( 2 ( cos ( x ) + ln ( π ) ) )}

- \frac{sin ( x )}{ln ( 2 cos ( x ) + 2 ln ( π ) )}

Solution steps

- \frac{sin ( x )}{ln ( 2 ( cos ( x ) + ln ( π ) ) )}

Expand

2 (cos (x) + ln (π)) : 2 cos (x) + 2 ln (π)

= - \frac{sin ( x )}{ln ( 2 cos ( x ) + 2 ln ( π ) )}

e ∣ x ∣ (x^{2} + 4 x y - 2 x)

(t^{2} - 2 t) e t

3 ((x + 4) (x + 2) (x + 1) (x - 4))

\frac{( x - 1 ) ( x + 5 )}{x - 4}

(m - 7 + 7) (m - 7 - 7)

What is expand-(sin(x))/(ln(2(cos(x)+ln(pi)))) ?
The solution to expand-(sin(x))/(ln(2(cos(x)+ln(pi)))) is -(sin(x))/(ln(2cos(x)+2ln(pi)))