What is expand (z-1-i)(z-1+i) ?

The solution to expand (z-1-i)(z-1+i) is z^2-2z+2

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expand (z-1-i)(z-1+i)

expand

(z - 1 - i) (z - 1 + i)

z^{2} - 2 z + 2

Solution steps

(z - 1 - i) (z - 1 + i)

Distribute parentheses

= zz + z (- 1) + z i - 1 \cdot z - 1 \cdot (- 1) - 1 i - i z - i (- 1) - ii

Simplify

zz + z (- 1) + z i - 1 \cdot z - 1 \cdot (- 1) - 1 i - i z - i (- 1) - ii : z^{2} - 2 z + 2

= z^{2} - 2 z + 2

(L - \frac{t}{2}) (r) (H + \frac{k}{2})^{2}

\frac{1}{s ( s + 1 ) ( s ^{2} + 6 s + 13 )}

\frac{x x ^{2} + 36 \cdot 3 - 2 ( x ^{2} + 36 )}{6 ( x ^{2} + 36 )}

ln (4) m^{3} n^{5}

\frac{( x ^{2} - 2 x + 1 )}{x ^{2} ( 2 x ^{2} + 1 )}

What is expand (z-1-i)(z-1+i) ?
The solution to expand (z-1-i)(z-1+i) is z^2-2z+2