What is expand ((x^2+1)dy-(xy-3x)dx=0)*(-1) ?

The solution to expand ((x^2+1)dy-(xy-3x)dx=0)*(-1) is -x^2dy-dy+xydx-3xdx=0

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expand ((x^2+1)dy-(xy-3x)dx=0)*(-1)

expand

((x^{2} + 1) d y - (x y - 3 x) d x = 0) \cdot (- 1)

- x^{2} d y - d y + x y d x - 3 x d x = 0

Solution steps

((x^{2} + 1) d y - (x y - 3 x) d x = 0) (- 1)

= (- 1) ((x^{2} + 1) d y - 0 = (x y - 3 x) d x)

Apply the distributive law:

a (b - c) = ab - a c

a = (- 1), b = (x^{2} + 1) d y, c = (x y - 3 x) d x = 0

(- 1) (x^{2} + 1) d y - (- 1) (x y - 3 x) d x = 0

Expand

(- 1) (x^{2} + 1) d y - (- 1) (x y - 3 x) d x : - x^{2} d y - d y + x y d x - 3 x d x

- x^{2} d y - d y + x y d x - 3 x d x = 0

\frac{x ^{2} + 9 x + 24}{( x + 4 ) ^{2} ( x + 3 )}

(1 + sin (x)) sin (x)

(- 4 r^{4} cos (θ) - 4 r sin (θ) + r)^{2}

(e^{15 x} + e^{- 15 x})^{2}

What is expand ((x^2+1)dy-(xy-3x)dx=0)*(-1) ?
The solution to expand ((x^2+1)dy-(xy-3x)dx=0)*(-1) is -x^2dy-dy+xydx-3xdx=0