What is expand (1+sin(x))sin(x) ?

The solution to expand (1+sin(x))sin(x) is sin(x)+sin^2(x)

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expand (1+sin(x))sin(x)

expand

(1 + sin (x)) sin (x)

sin (x) + sin^{2} (x)

Solution steps

(1 + sin (x)) sin (x)

= sin (x) (1 + sin (x))

Apply the distributive law:

a (b + c) = ab + a c

sin (x) (1 + sin (x)) = sin (x) \cdot 1 + sin (x) sin (x)

= sin (x) \cdot 1 + sin (x) sin (x)

Simplify

sin (x) \cdot 1 + sin (x) sin (x) : sin (x) + sin^{2} (x)

= sin (x) + sin^{2} (x)

(- 4 r^{4} cos (θ) - 4 r sin (θ) + r)^{2}

(e^{15 x} + e^{- 15 x})^{2}

\frac{a + 8}{( a - 2 ) ( a - 9 )}

- \frac{4 ( x + 4 ) ^{2}}{9}

What is expand (1+sin(x))sin(x) ?
The solution to expand (1+sin(x))sin(x) is sin(x)+sin^2(x)