What is (0.00550368)/(s(0.00224+s^2+0.00182s)) ?

The solution to (0.00550368)/(s(0.00224+s^2+0.00182s)) is (17199)/(3125000s(0.00224+s^2+0.00182s))

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simplify (0.00550368)/(s(0.00224+s^2+0.00182s))

simplify

\frac{0.00550368}{s ( 0.00224 + s ^{2} + 0.00182 s )}

\frac{17199}{3125000 s ( 0.00224 + s ^{2} + 0.00182 s )}

Solution steps

\frac{0.00550368}{s ( 0.00224 + s ^{2} + 0.00182 s )}

Simplify

\frac{0.00550368}{s ( 0.00224 + s ^{2} + 0.00182 s )} : \frac{550368}{100000000 s ( 0.00224 + s ^{2} + 0.00182 s )}

= \frac{550368}{100000000 s ( 0.00224 + s ^{2} + 0.00182 s )}

Factor the number:

550368 = 32 \cdot 17199

= \frac{32 \cdot 17199}{100000000 s ( 0.00224 + s ^{2} + 0.00182 s )}

Factor the number:

100000000 = 32 \cdot 3125000

= \frac{32 \cdot 17199}{32 \cdot 3125000 s ( 0.00224 + s ^{2} + 0.00182 s )}

Cancel the common factor:

32

= \frac{17199}{3125000 s ( 0.00224 + s ^{2} + 0.00182 s )}

(y e^{x y} - \frac{1}{y ^{2}}) \cdot (e^{x^{2}} \cdot 2 x + 4 x)

(- \frac{x ^{2}}{3} - 1) (2 x - 2)

- \frac{u ( 16 x ^{6} - 14 u - 7 u x ^{2} )}{2 x}

6 (2 + 5)

s q r (4 + (2 tan^{2} (x)))

What is (0.00550368)/(s(0.00224+s^2+0.00182s)) ?
The solution to (0.00550368)/(s(0.00224+s^2+0.00182s)) is (17199)/(3125000s(0.00224+s^2+0.00182s))