What is expand-(u(16x^6-14u-7ux^2))/(2x) ?

The solution to expand-(u(16x^6-14u-7ux^2))/(2x) is -8ux^5+(7u^2)/x+(7u^2x)/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand-(u(16x^6-14u-7ux^2))/(2x)

expand

- \frac{u ( 16 x ^{6} - 14 u - 7 u x ^{2} )}{2 x}

- 8 u x^{5} + \frac{7 u ^{2}}{x} + \frac{7 u ^{2} x}{2}

Solution steps

- \frac{u ( 16 x ^{6} - 14 u - 7 u x ^{2} )}{2 x}

Expand

u (16 x^{6} - 14 u - 7 u x^{2}) : 16 u x^{6} - 14 u^{2} - 7 u^{2} x^{2}

= - \frac{- 14 u ^{2} - 7 u ^{2} x ^{2} + 16 u x ^{6}}{2 x}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{16 u x ^{6} - 14 u ^{2} - 7 u ^{2} x ^{2}}{2 x} = - (\frac{16 u x ^{6}}{2 x}) - (- \frac{14 u ^{2}}{2 x}) - (- \frac{7 u ^{2} x ^{2}}{2 x})

= - (\frac{16 u x ^{6}}{2 x}) - (- \frac{14 u ^{2}}{2 x}) - (- \frac{7 u ^{2} x ^{2}}{2 x})

Remove parentheses:

(a) = a, - (- a) = a

= - \frac{16 u x ^{6}}{2 x} + \frac{14 u ^{2}}{2 x} + \frac{7 u ^{2} x ^{2}}{2 x}

Cancel

\frac{16 u x ^{6}}{2 x} : 8 u x^{5}

= - 8 u x^{5} + \frac{14 u ^{2}}{2 x} + \frac{7 u ^{2} x ^{2}}{2 x}

Divide the numbers:

\frac{14}{2} = 7

= - 8 u x^{5} + \frac{7 u ^{2}}{x} + \frac{7 u ^{2} x ^{2}}{2 x}

Cancel

\frac{7 u ^{2} x ^{2}}{2 x} : \frac{7 u ^{2} x}{2}

= - 8 u x^{5} + \frac{7 u ^{2}}{x} + \frac{7 u ^{2} x}{2}

6 (2 + 5)

s q r (4 + (2 tan^{2} (x)))

\frac{( k + 2 ) ! + ( k + 1 ) ( k + 1 ) !}{( k + 1 ) ! + ( k + 2 ) !}

2 x (4 x - 1) (2 x + 9) (x - 5) (x + 5)

(s - 1) (s + 1 + j^{2} π) (s + 1 - j^{2} π)

What is expand-(u(16x^6-14u-7ux^2))/(2x) ?
The solution to expand-(u(16x^6-14u-7ux^2))/(2x) is -8ux^5+(7u^2)/x+(7u^2x)/2