What is expand (s-1)(s+1+j^2pi)(s+1-j^2pi) ?

The solution to expand (s-1)(s+1+j^2pi)(s+1-j^2pi) is s^3+s^2-pi^2j^4s-s+pi^2j^4-1

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expand (s-1)(s+1+j^2pi)(s+1-j^2pi)

expand

(s - 1) (s + 1 + j^{2} π) (s + 1 - j^{2} π)

s^{3} + s^{2} - π^{2} j^{4} s - s + π^{2} j^{4} - 1

Solution steps

(s - 1) (s + 1 + j^{2} π) (s + 1 - j^{2} π)

= (s - 1) (s + 1 + π j^{2}) (s + 1 - π j^{2})

Expand

(s - 1) (s + 1 + j^{2} π) : π j^{2} s + s^{2} - π j^{2} - 1

= (π j^{2} s + s^{2} - π j^{2} - 1) (s + 1 - j^{2} π)

Expand

(π j^{2} s + s^{2} - π j^{2} - 1) (s + 1 - j^{2} π) : s^{3} + s^{2} - π^{2} j^{4} s - s + π^{2} j^{4} - 1

= s^{3} + s^{2} - π^{2} j^{4} s - s + π^{2} j^{4} - 1

2 ln^{2} (2) - 2 (2 ln (2) - 2)

\frac{10 x ^{3} - 6 x ^{2} + 15}{( x ^{3} - 3 ) ^{2}}

(2 n - 3) x + 5 n (x - 4 = 3)

- \frac{21 x}{128} + \frac{21}{256} - \frac{x}{32} + \frac{1}{32}

(1 + cos (x))^{2} + (- sin (x))

What is expand (s-1)(s+1+j^2pi)(s+1-j^2pi) ?
The solution to expand (s-1)(s+1+j^2pi)(s+1-j^2pi) is s^3+s^2-pi^2j^4s-s+pi^2j^4-1