What is expand (10x^3-6x^2+15)/((x^3-3)^2) ?

The solution to expand (10x^3-6x^2+15)/((x^3-3)^2) is (10x^3-6x^2+15)/(x^6-6x^3+9)

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expand (10x^3-6x^2+15)/((x^3-3)^2)

expand

\frac{10 x ^{3} - 6 x ^{2} + 15}{( x ^{3} - 3 ) ^{2}}

\frac{10 x ^{3} - 6 x ^{2} + 15}{x ^{6} - 6 x ^{3} + 9}

Solution steps

\frac{10 x ^{3} - 6 x ^{2} + 15}{( x ^{3} - 3 ) ^{2}}

(x^{3} - 3)^{2} = x^{6} - 6 x^{3} + 9

= \frac{10 x ^{3} - 6 x ^{2} + 15}{x ^{6} - 6 x ^{3} + 9}

(2 n - 3) x + 5 n (x - 4 = 3)

- \frac{21 x}{128} + \frac{21}{256} - \frac{x}{32} + \frac{1}{32}

(1 + cos (x))^{2} + (- sin (x))

[\frac{8}{x - 16} + 2 (100 - x)] (x - 16)

\frac{2}{n} (1 + \frac{2 i}{n})^{3}

What is expand (10x^3-6x^2+15)/((x^3-3)^2) ?
The solution to expand (10x^3-6x^2+15)/((x^3-3)^2) is (10x^3-6x^2+15)/(x^6-6x^3+9)