What is (1/4 (1/4-1)(1/4-2))/(3!) ?

The solution to (1/4 (1/4-1)(1/4-2))/(3!) is 7/128

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simplify (1/4 (1/4-1)(1/4-2))/(3!)

simplify

\frac{\frac{1}{4} ( \frac{1}{4} - 1 ) ( \frac{1}{4} - 2 )}{3 !}

\frac{7}{128}

Decimal Notation

0.0546875

Solution steps

\frac{\frac{1}{4} ( \frac{1}{4} - 1 ) ( \frac{1}{4} - 2 )}{3 !}

\frac{1}{4} (\frac{1}{4} - 1) (\frac{1}{4} - 2) = \frac{21}{64}

= \frac{\frac{21}{64}}{3 !}

Apply the fraction rule:

\frac{\frac{a}{b}}{c} = \frac{a}{b \cdot c}

= \frac{21}{64 \cdot 3 !}

64 \cdot 3! = 384

= \frac{21}{384}

Cancel

\frac{21}{384} : \frac{7}{128}

= \frac{7}{128}

s^{4} + 12 s^{3} + 64 s^{2} + 128 s

\frac{( 2 e ^{(- x^{2} - 4 y^{2})} y - 8 e ^{(- x^{2} - 4 y^{2})} y ( 4 x ^{2} + y ^{2} ) )}{2 e ^{(- x^{2} - 4 y^{2})} y}

5 x^{2} - 8 x + 3 = 0

u^{2} - ux + 2 u - 2 x

\frac{1}{5} - \frac{1}{2} + \frac{1}{3}

What is (1/4 (1/4-1)(1/4-2))/(3!) ?
The solution to (1/4 (1/4-1)(1/4-2))/(3!) is 7/128