What are the solutions to the equation 6a^2+8a-25=-3 ?

The solutions to the equation 6a^2+8a-25=-3 are a=(-2+sqrt(37))/3 ,a=-(2+sqrt(37))/3

Find the zeros of 6a^2+8a-25=-3

The zeros of 6a^2+8a-25=-3 are a=(-2+sqrt(37))/3 ,a=-(2+sqrt(37))/3

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6 a^{2} + 8 a - 25 = - 3

a = \frac{- 2 + 37}{3}, a = - \frac{2 + 37}{3}

Decimal Notation

a = 1.36092 \dots, a = - 2.69425 \dots

Solution steps

6 a^{2} + 8 a - 25 = - 3

Move

3

to the left side

6 a^{2} + 8 a - 22 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 6 ( - 22 )}{2 \cdot 6}

8^{2} - 4 \cdot 6 (- 22) = 437

a_{1, 2} = \frac{- 8 \pm 4 37}{2 \cdot 6}

Separate the solutions

a_{1} = \frac{- 8 + 4 37}{2 \cdot 6}, a_{2} = \frac{- 8 - 4 37}{2 \cdot 6}

a = \frac{- 8 + 4 37}{2 \cdot 6} : \frac{- 2 + 37}{3}

a = \frac{- 8 - 4 37}{2 \cdot 6} : - \frac{2 + 37}{3}

The solutions to the quadratic equation are:

a = \frac{- 2 + 37}{3}, a = - \frac{2 + 37}{3}

- 37 x^{2} + x^{4} + 36

8 (3 m - 2) - 7 m = 0

y^{2} - 11 y + 18

- 12 x^{2} - 36 x = 0

6 x^{2} + 13 x = 5

What are the solutions to the equation 6a^2+8a-25=-3 ?
The solutions to the equation 6a^2+8a-25=-3 are a=(-2+sqrt(37))/3 ,a=-(2+sqrt(37))/3
Find the zeros of 6a^2+8a-25=-3
The zeros of 6a^2+8a-25=-3 are a=(-2+sqrt(37))/3 ,a=-(2+sqrt(37))/3