What is expand (x-3)dx+4(x+y-1)dy ?

The solution to expand (x-3)dx+4(x+y-1)dy is xdx-3dx+4xdy+4ydy-4dy

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expand (x-3)dx+4(x+y-1)dy

expand

(x - 3) d x + 4 (x + y - 1) d y

x d x - 3 d x + 4 x d y + 4 y d y - 4 d y

Solution steps

(x - 3) d x + 4 (x + y - 1) d y

Expand

d x (x - 3) : x d x - 3 d x

= x d x - 3 d x + 4 (x + y - 1) d y

Expand

4 d y (x + y - 1) : 4 x d y + 4 y d y - 4 d y

= x d x - 3 d x + 4 x d y + 4 y d y - 4 d y

sin (t) u (t - π)

2 (x + 1^{2} = 32)

(6 x^{2} - 5 x y - 2 y^{2}) d x - (6 x^{2} - 8 x y - y^{2}) d y

\frac{x t}{( 3 x ^{2} + 2 ) ( 9 t ^{2} x ^{4} + 12 t ^{2} x ^{2} + 4 t ^{2} + 6 )}

((4 x + 2) - 4 x) \cdot ((4 x + 2) + 4 x)

What is expand (x-3)dx+4(x+y-1)dy ?
The solution to expand (x-3)dx+4(x+y-1)dy is xdx-3dx+4xdy+4ydy-4dy