What is expand ((2^{k+1}))/((k+1)!) ?

The solution to expand ((2^{k+1}))/((k+1)!) is (2^{k+1})/((k+1)!)

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expand ((2^{k+1}))/((k+1)!)

expand

\frac{( 2 ^{k + 1} )}{( k + 1 ) !}

\frac{2 ^{k + 1}}{( k + 1 ) !}

Solution steps

\frac{( 2 ^{k + 1} )}{( k + 1 ) !}

Remove parentheses:

(a) = a

= \frac{2 ^{k + 1}}{( k + 1 ) !}

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- (- cos (θ) - λ) (\frac{1}{2} sin^{2} (θ))

a sin (x) - cos (x) - a cos (x) (3 sin (x) + 4 cos (x))

- 2 (93 + 5113)

\frac{( x - y ) ^{2}}{4 x ^{6}}

What is expand ((2^{k+1}))/((k+1)!) ?
The solution to expand ((2^{k+1}))/((k+1)!) is (2^{k+1})/((k+1)!)