What is expand ((3a)/2-(2b)/3)^2 ?

The solution to expand ((3a)/2-(2b)/3)^2 is (-72ab+81a^2+16b^2)/(36)

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expand ((3a)/2-(2b)/3)^2

expand

(\frac{3 a}{2} - \frac{2 b}{3})^{2}

\frac{- 72 ab + 81 a ^{2} + 16 b ^{2}}{36}

Solution steps

(\frac{3 a}{2} - \frac{2 b}{3})^{2}

Apply Perfect Square Formula:

(a - b)^{2} = a^{2} - 2 ab + b^{2}

(\frac{3 a}{2} - \frac{2 b}{3})^{2} = (\frac{3 a}{2})^{2} - 2 \cdot \frac{3 a}{2} \cdot \frac{2 b}{3} + (\frac{2 b}{3})^{2}

= (\frac{3 a}{2})^{2} - 2 \cdot \frac{3 a}{2} \cdot \frac{2 b}{3} + (\frac{2 b}{3})^{2}

Simplify

(\frac{3 a}{2})^{2} - 2 \cdot \frac{3 a}{2} \cdot \frac{2 b}{3} + (\frac{2 b}{3})^{2} : \frac{- 72 ab + 81 a ^{2} + 16 b ^{2}}{36}

= \frac{- 72 ab + 81 a ^{2} + 16 b ^{2}}{36}

\frac{3 ( y + 2 )}{2}

(f \circ g) (x - 5)

(7 + 22) (7 - 22)

\frac{( 3 - x ) ( 1 + x )}{( 4 - x )}

2 x sin (y) + 3 (y - \frac{π}{6}) + 1

What is expand ((3a)/2-(2b)/3)^2 ?
The solution to expand ((3a)/2-(2b)/3)^2 is (-72ab+81a^2+16b^2)/(36)