What is 1/8 (arcsin(y)-1/4 sin(4arcsin(y))) ?

The solution to 1/8 (arcsin(y)-1/4 sin(4arcsin(y))) is (arcsin(y)-1/4 sin(4arcsin(y)))/8

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simplify 1/8 (arcsin(y)-1/4 sin(4arcsin(y)))

simplify

\frac{1}{8} (arcsin (y) - \frac{1}{4} sin (4 arcsin (y)))

\frac{arcsin ( y ) - \frac{1}{4} sin ( 4 arcsin ( y ) )}{8}

Solution steps

\frac{1}{8} (arcsin (y) - \frac{1}{4} sin (4 arcsin (y)))

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot ( arcsin ( y ) - \frac{1}{4} sin ( 4 arcsin ( y ) ) )}{8}

Apply rule:

1 \cdot a = a

1 \cdot (arcsin (y) - \frac{1}{4} sin (4 arcsin (y))) = (arcsin (y) - \frac{1}{4} sin (4 arcsin (y)))

= \frac{arcsin ( y ) - \frac{1}{4} sin ( 4 arcsin ( y ) )}{8}

(cos^{2} (x) + sin^{2} (x))^{2}

(cos (θ) + i sin (θ))^{2} (1 + 2 cos (θ))

(3 x - 5 y = 4,) (3 x - 2 y = 12)

\frac{x + y i - 3}{( x + y i ) ^{2} + 2 ( x + y i ) + 2}

\frac{1}{s ( s ^{3} + 6 s ^{2} + 11 x + 6 )}

What is 1/8 (arcsin(y)-1/4 sin(4arcsin(y))) ?
The solution to 1/8 (arcsin(y)-1/4 sin(4arcsin(y))) is (arcsin(y)-1/4 sin(4arcsin(y)))/8