What is 5/(a^2+3a+2)+(5a+1)/(a^2+3a+2) ?

The solution to 5/(a^2+3a+2)+(5a+1)/(a^2+3a+2) is (5a+6)/(a^2+3a+2)

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simplify 5/(a^2+3a+2)+(5a+1)/(a^2+3a+2)

simplify

\frac{5}{a ^{2} + 3 a + 2} + \frac{5 a + 1}{a ^{2} + 3 a + 2}

\frac{5 a + 6}{a ^{2} + 3 a + 2}

Solution steps

\frac{5}{a ^{2} + 3 a + 2} + \frac{5 a + 1}{a ^{2} + 3 a + 2}

Apply the fraction rule:

\frac{a}{c} + \frac{b}{c} = \frac{a + b}{c}

= \frac{5 + 5 a + 1}{a ^{2} + 3 a + 2}

Simplify

5 + 5 a + 1 : 5 a + 6

= \frac{5 a + 6}{a ^{2} + 3 a + 2}

18 \leq 3 (b - 4)

- 4 (\frac{x + 1}{4}) > x - 8 (\frac{2}{3 - x})

- y^{2} + yz - x y

\frac{1}{2} 9

6 mn - 5 m^{2} n^{2} - 9 m n^{2} - 11 mn + 10 m n^{2} + 5 m^{2} n^{2}

What is 5/(a^2+3a+2)+(5a+1)/(a^2+3a+2) ?
The solution to 5/(a^2+3a+2)+(5a+1)/(a^2+3a+2) is (5a+6)/(a^2+3a+2)