What is expand (2(\sqrt[3]{x}-1))/(3x^{2/3)} ?

The solution to expand (2(\sqrt[3]{x}-1))/(3x^{2/3)} is 2/(3x^{1/3)}-2/(3x^{2/3)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (2(\sqrt[3]{x}-1))/(3x^{2/3)}

expand

\frac{2}{3 x ^{\frac{1}{3}}} - \frac{2}{3 x ^{\frac{2}{3}}}

Solution steps

Expand

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

Cancel

= \frac{2}{3 x ^{\frac{1}{3}}} - \frac{2}{3 x ^{\frac{2}{3}}}

A (3, - 1) B (4, 3)

3 (3 x^{2} - 3) - 2

\frac{x ^{4} y ^{4}}{( x ^{2} + y ^{4} ) ^{3}}

\frac{d}{d x} ((z (x, y)) (4 - x^{2} - y^{2}))

- \frac{1}{( 1 - j w ) ( 3 - j w ) ^{2}}

What is expand (2(\sqrt[3]{x}-1))/(3x^{2/3)} ?
The solution to expand (2(\sqrt[3]{x}-1))/(3x^{2/3)} is 2/(3x^{1/3)}-2/(3x^{2/3)}