What is expand-1/((1-jw)(3-jw)^2) ?

The solution to expand-1/((1-jw)(3-jw)^2) is -1/(-j^3w^3+7j^2w^2-15jw+9)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand-1/((1-jw)(3-jw)^2)

expand

- \frac{1}{( 1 - j w ) ( 3 - j w ) ^{2}}

- \frac{1}{- j ^{3} w ^{3} + 7 j ^{2} w ^{2} - 15 j w + 9}

Solution steps

- \frac{1}{( 1 - j w ) ( 3 - j w ) ^{2}}

(3 - j w)^{2} = 9 - 6 j w + j^{2} w^{2}

= - \frac{1}{( - j w + 1 ) ( j ^{2} w ^{2} - 6 j w + 9 )}

Expand

(1 - j w) (9 - 6 j w + j^{2} w^{2}) : - j^{3} w^{3} + 7 j^{2} w^{2} - 15 j w + 9

= - \frac{1}{- j ^{3} w ^{3} + 7 j ^{2} w ^{2} - 15 j w + 9}

(52 x - 675 - x^{2}) (x + 5)

\frac{cos ( \frac{x}{y} ) ( y - x \frac{d y}{d x} )}{y ^{2}}

(20 G (C) - 80 C = 4, 6) (100 G (C) - 160 C = 140)

(\frac{1}{2} \cdot x - \frac{1}{2})^{10}

x^{\frac{3}{5}} (x - 8)

What is expand-1/((1-jw)(3-jw)^2) ?
The solution to expand-1/((1-jw)(3-jw)^2) is -1/(-j^3w^3+7j^2w^2-15jw+9)