What is expand-e^{2jkw}(e^{4jkw}+e^{-4jkw}) ?

The solution to expand-e^{2jkw}(e^{4jkw}+e^{-4jkw}) is -e^{6jkw}-e^{-2jkw}

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expand-e^{2jkw}(e^{4jkw}+e^{-4jkw})

expand

- e^{2 jk w} (e^{4 jk w} + e^{- 4 jk w})

- e^{6 jk w} - e^{- 2 jk w}

Solution steps

- e^{2 jk w} (e^{4 jk w} + e^{- 4 jk w})

Apply the distributive law:

a (b + c) = ab + a c

a = - e^{2 jk w}, b = e^{4 jk w}, c = e^{- 4 jk w}

= - e^{2 jk w} e^{4 jk w} + (- e^{2 jk w}) e^{- 4 jk w}

Apply minus-plus rules

+ (- a) = - a

= - e^{2 jk w} e^{4 jk w} - e^{2 jk w} e^{- 4 jk w}

Simplify

- e^{2 jk w} e^{4 jk w} - e^{2 jk w} e^{- 4 jk w} : - e^{6 jk w} - e^{- 2 jk w}

= - e^{6 jk w} - e^{- 2 jk w}

A (4, 6) B (0, - 16)

(4 - \frac{b}{c}) (\frac{b}{c} + 4)

- \frac{2 ( 3 + 3 )}{3}

3 i (3 - 6 i)^{2}

\frac{4 ( x ^{2} - 4 x )}{( x - 2 ) ^{2}}

What is expand-e^{2jkw}(e^{4jkw}+e^{-4jkw}) ?
The solution to expand-e^{2jkw}(e^{4jkw}+e^{-4jkw}) is -e^{6jkw}-e^{-2jkw}