What is expand (x+4)/((3x+2)(x-8)) ?

The solution to expand (x+4)/((3x+2)(x-8)) is (x+4)/(3x^2-22x-16)

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expand (x+4)/((3x+2)(x-8))

expand

\frac{x + 4}{( 3 x + 2 ) ( x - 8 )}

\frac{x + 4}{3 x ^{2} - 22 x - 16}

Solution steps

\frac{x + 4}{( 3 x + 2 ) ( x - 8 )}

Expand

(3 x + 2) (x - 8) : 3 x^{2} - 22 x - 16

= \frac{x + 4}{3 x ^{2} - 22 x - 16}

\frac{( 3 x + 4 ) ( x - 9 )}{( x - 2 ) ( x + 2 )}

\frac{1}{2} (x - 3)^{2} (x + 1)^{3}

\frac{4}{( s + 2 ) ^{2}}

\frac{( e ^{- s} + s ^{2} + s + 10 )}{( s + 4 ) ( s - 2 ) ( s - 1 )}

\frac{s ^{2} + 9 s + 10}{( s + 1 ) ( s ^{2} + 5 s + 6 )}

What is expand (x+4)/((3x+2)(x-8)) ?
The solution to expand (x+4)/((3x+2)(x-8)) is (x+4)/(3x^2-22x-16)