What is (d^2)/(dt^2)((h)(3t^2-2t+4+e^{-10t})) ?

The answer to (d^2)/(dt^2)((h)(3t^2-2t+4+e^{-10t})) is h(100e^{-10t}+6)

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(d^2)/(dt^2)((h)(3t^2-2t+4+e^{-10t}))

\frac{d ^{2}}{d t ^{2}} ((h) (3 t^{2} - 2 t + 4 + e^{- 10 t}))

h (100 e^{- 10 t} + 6)

Solution steps

\frac{d ^{2}}{d t ^{2}} ((h) (3 t^{2} - 2 t + 4 + e^{- 10 t}))

\frac{d}{d t} (h (3 t^{2} - 2 t + 4 + e^{- 10 t})) = h (6 t - 10 e^{- 10 t} - 2)

= \frac{d}{d t} (h (6 t - 10 e^{- 10 t} - 2))

\frac{d}{d t} (h (6 t - 10 e^{- 10 t} - 2)) = h (100 e^{- 10 t} + 6)

= h (100 e^{- 10 t} + 6)

- 5 (- 7 - 2)

\frac{2 x c ( x - b )}{- 2 b + x + a}

(2 x + \frac{1}{3}) 2

(\frac{x}{3} - \frac{4}{5}) (\frac{x}{3} + \frac{4}{5})

(f \circ g) x^{3} (4 x^{2} - 5 x + 9) - 1

What is (d^2)/(dt^2)((h)(3t^2-2t+4+e^{-10t})) ?
The answer to (d^2)/(dt^2)((h)(3t^2-2t+4+e^{-10t})) is h(100e^{-10t}+6)