What is expand (x+3)^2\delta(x-5) ?

The solution to expand (x+3)^2\delta(x-5) is x^2\delta(x-5)+6x\delta(x-5)+9\delta(x-5)

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expand (x+3)^2\delta(x-5)

expand

(x + 3)^{2} δ (x - 5)

x^{2} δ (x - 5) + 6 x δ (x - 5) + 9 δ (x - 5)

Solution steps

(x + 3)^{2} δ (x - 5)

(x + 3)^{2} = x^{2} + 6 x + 9

= δ (x - 5) (x^{2} + 6 x + 9)

= δ (x - 5) (x^{2} + 6 x + 9)

Distribute parentheses

= δ (x - 5) x^{2} + δ (x - 5) \cdot 6 x + δ (x - 5) \cdot 9

= x^{2} δ (x - 5) + 6 x δ (x - 5) + 9 δ (x - 5)

(- 3)^{2}

\frac{cos ( θ ) ( 1 + sin ( θ ) )}{1 + sin ^{2} ( θ )}

- \frac{( x + 6 ) ^{2}}{4}

(x^{2} - v^{2} x^{2}) (v d x + x d v)

\frac{z x ^{2} - z ^{2}}{4} + \frac{z ( P - z - 2 x )}{2}

What is expand (x+3)^2\delta(x-5) ?
The solution to expand (x+3)^2\delta(x-5) is x^2\delta(x-5)+6x\delta(x-5)+9\delta(x-5)