What is (x-1)(x-3/2)(x+1)(x+3) ?

The solution to (x-1)(x-3/2)(x+1)(x+3) is ((x-1)(2x-3)(x+1)(x+3))/2

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simplify (x-1)(x-3/2)(x+1)(x+3)

simplify

(x - 1) (x - \frac{3}{2}) (x + 1) (x + 3)

\frac{( x - 1 ) ( 2 x - 3 ) ( x + 1 ) ( x + 3 )}{2}

Solution steps

(x - 1) (x - \frac{3}{2}) (x + 1) (x + 3)

Simplify

x - \frac{3}{2} : \frac{2 x - 3}{2}

= (x - 1) \frac{2 x - 3}{2} (x + 1) (x + 3)

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{( x - 1 ) ( 2 x - 3 ) ( x + 1 ) ( x + 3 )}{2}

27 (- 50 - \frac{150}{e ^{2}} - \frac{100}{e ^{3}})

e^{t} (t^{2} + 2 t - 2)

(2 x - \frac{2}{7} y)^{2}

(2^{\frac{1}{2}} + 1)^{3}

- (4 x^{4} - 4 x^{2} + 5) (10 x^{\frac{2}{3}})

What is (x-1)(x-3/2)(x+1)(x+3) ?
The solution to (x-1)(x-3/2)(x+1)(x+3) is ((x-1)(2x-3)(x+1)(x+3))/2