What is x^2(2x^3-3/(4x^4)) ?

The solution to x^2(2x^3-3/(4x^4)) is (8x^7-3)/(4x^2)

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simplify x^2(2x^3-3/(4x^4))

simplify

x^{2} (2 x^{3} - \frac{3}{4 x ^{4}})

\frac{8 x ^{7} - 3}{4 x ^{2}}

Solution steps

x^{2} (2 x^{3} - \frac{3}{4 x ^{4}})

Join

2 x^{3} - \frac{3}{4 x ^{4}} : \frac{8 x ^{7} - 3}{4 x ^{4}}

= x^{2} \frac{8 x ^{7} - 3}{4 x ^{4}}

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{x ^{2} ( 8 x ^{7} - 3 )}{4 x ^{4}}

Apply exponent rule:

a^{b + c} = a^{b} \cdot a^{c}

x^{4} = x^{2} x^{2}

= \frac{x ^{2} ( 8 x ^{7} - 3 )}{4 x ^{2} x ^{2}}

Cancel the common factor:

x^{2}

= \frac{8 x ^{7} - 3}{4 x ^{2}}

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(- \frac{6}{x ^{4}} - \frac{4}{x ^{5}}) (x^{3} + 7 x - 8)

\frac{1}{( x ^{2} ( x - 1 ) )}

\frac{( ( 5 x - k ) ^{2} )}{x}

What is x^2(2x^3-3/(4x^4)) ?
The solution to x^2(2x^3-3/(4x^4)) is (8x^7-3)/(4x^2)