What is (-6/(x^4)-4/(x^5))(x^3+7x-8) ?

The solution to (-6/(x^4)-4/(x^5))(x^3+7x-8) is ((-6x-4)(x^3+7x-8))/(x^5)

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simplify (-6/(x^4)-4/(x^5))(x^3+7x-8)

simplify

(- \frac{6}{x ^{4}} - \frac{4}{x ^{5}}) (x^{3} + 7 x - 8)

\frac{( - 6 x - 4 ) ( x ^{3} + 7 x - 8 )}{x ^{5}}

Solution steps

(- \frac{6}{x ^{4}} - \frac{4}{x ^{5}}) (x^{3} + 7 x - 8)

Join

- \frac{6}{x ^{4}} - \frac{4}{x ^{5}} : \frac{- 6 x - 4}{x ^{5}}

= \frac{- 6 x - 4}{x ^{5}} (x^{3} + 7 x - 8)

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{( - 6 x - 4 ) ( x ^{3} + 7 x - 8 )}{x ^{5}}

\frac{1}{( x ^{2} ( x - 1 ) )}

\frac{( ( 5 x - k ) ^{2} )}{x}

\frac{4 x}{( x + 1 ) ^{2}}

\frac{5 x ^{2} - 3 x + 10}{( x - 1 ) ( x ^{2} + 3 )}

\frac{s ^{2} + 6 s + 19}{( s + 5 ) ( s + 25 )}

What is (-6/(x^4)-4/(x^5))(x^3+7x-8) ?
The solution to (-6/(x^4)-4/(x^5))(x^3+7x-8) is ((-6x-4)(x^3+7x-8))/(x^5)