What is expand (5x^2-3x+10)/((x-1)(x^2+3)) ?

The solution to expand (5x^2-3x+10)/((x-1)(x^2+3)) is (5x^2-3x+10)/(x^3+3x-x^2-3)

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expand (5x^2-3x+10)/((x-1)(x^2+3))

expand

\frac{5 x ^{2} - 3 x + 10}{( x - 1 ) ( x ^{2} + 3 )}

\frac{5 x ^{2} - 3 x + 10}{x ^{3} + 3 x - x ^{2} - 3}

Solution steps

\frac{5 x ^{2} - 3 x + 10}{( x - 1 ) ( x ^{2} + 3 )}

Expand

(x - 1) (x^{2} + 3) : x^{3} + 3 x - x^{2} - 3

= \frac{5 x ^{2} - 3 x + 10}{x ^{3} + 3 x - x ^{2} - 3}

\frac{s ^{2} + 6 s + 19}{( s + 5 ) ( s + 25 )}

x \cdot (\frac{384}{x - 12} + 8)

8 (x - \frac{4}{5})

e^{2 x} \cdot (2 x e^{2 x} + e^{2 x})

\frac{t ^{3} + 2 t ^{2} - 3 + 1}{t t}

What is expand (5x^2-3x+10)/((x-1)(x^2+3)) ?
The solution to expand (5x^2-3x+10)/((x-1)(x^2+3)) is (5x^2-3x+10)/(x^3+3x-x^2-3)