What is expand (3(t+1)(t-1))/(t-2) ?

The solution to expand (3(t+1)(t-1))/(t-2) is (3t^2-3)/(t-2)

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expand (3(t+1)(t-1))/(t-2)

expand

\frac{3 ( t + 1 ) ( t - 1 )}{t - 2}

\frac{3 t ^{2} - 3}{t - 2}

Solution steps

\frac{3 ( t + 1 ) ( t - 1 )}{t - 2}

Expand

3 (t + 1) (t - 1) : 3 t^{2} - 3

= \frac{3 t ^{2} - 3}{t - 2}

(2 e^{2 r} sin (3 θ)) (s - 2 t)

(4 k - x m) (k z^{2} - x \frac{m z ^{2}}{4})

(\frac{7}{9} + \frac{2}{9})^{9}

\frac{1}{x - 2} - \frac{4}{x ^{2} - 4}

\frac{( 2 + j ) ( 0.6 + j ^{0.8} )}{- 4 + j} - j

What is expand (3(t+1)(t-1))/(t-2) ?
The solution to expand (3(t+1)(t-1))/(t-2) is (3t^2-3)/(t-2)