What is the d/(dt)((x)(-2611t^2+29112t+6844)) ?

The d/(dt)((x)(-2611t^2+29112t+6844)) is (dx)/(dt)(-2611t^2+29112t+6844)+(-5222t+29112)x

What is the first d/(dt)((x)(-2611t^2+29112t+6844)) ?

The first d/(dt)((x)(-2611t^2+29112t+6844)) is (dx)/(dt)(-2611t^2+29112t+6844)+(-5222t+29112)x

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d t} ((x) (- 2611 t^{2} + 29112 t + 6844))

\frac{d x}{d t} (- 2611 t^{2} + 29112 t + 6844) + (- 5222 t + 29112) x

Solution steps

\frac{d}{d t} ((x) (- 2611 t^{2} + 29112 t + 6844))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x, g = - 2611 t^{2} + 29112 t + 6844

= \frac{d x}{d t} (- 2611 t^{2} + 29112 t + 6844) + \frac{d}{d t} (- 2611 t^{2} + 29112 t + 6844) x

\frac{d}{d t} (- 2611 t^{2} + 29112 t + 6844) = - 5222 t + 29112

= \frac{d x}{d t} (- 2611 t^{2} + 29112 t + 6844) + (- 5222 t + 29112) x

A (- 3, - 2) B (1, - 2) C (1, 2)

4 a (a + a)

(x^{3} - 3 x y)^{2} + (3 x^{2} y - y^{3})^{2}

(1 - \frac{1}{z}) (1 - \frac{0.2}{z})

\frac{( s ^{2} + s + 1 )}{( s ^{2} + 1 ) ( s + 2 ) ( s + 4 )}

What is the d/(dt)((x)(-2611t^2+29112t+6844)) ?
The d/(dt)((x)(-2611t^2+29112t+6844)) is (dx)/(dt)(-2611t^2+29112t+6844)+(-5222t+29112)x
What is the first d/(dt)((x)(-2611t^2+29112t+6844)) ?
The first d/(dt)((x)(-2611t^2+29112t+6844)) is (dx)/(dt)(-2611t^2+29112t+6844)+(-5222t+29112)x