What is expand (x-3)/((x+1)(x-6)) ?

The solution to expand (x-3)/((x+1)(x-6)) is (x-3)/(x^2-5x-6)

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expand (x-3)/((x+1)(x-6))

expand

\frac{x - 3}{( x + 1 ) ( x - 6 )}

\frac{x - 3}{x ^{2} - 5 x - 6}

Solution steps

\frac{x - 3}{( x + 1 ) ( x - 6 )}

Expand

(x + 1) (x - 6) : x^{2} - 5 x - 6

= \frac{x - 3}{x ^{2} - 5 x - 6}

\frac{1}{( 3 n - 4 a ^{3} ) ^{2}}

(cos (5 x) + cos (10 x) + cos (15 x))^{2}

\frac{3 h}{[ ( x + 7 ) ( x + h + 7 ) ]}

2 (62329 - 223)

2 (7^{\frac{1}{12}} - 1)

What is expand (x-3)/((x+1)(x-6)) ?
The solution to expand (x-3)/((x+1)(x-6)) is (x-3)/(x^2-5x-6)