What is expand 1/((3n-4a^3)^2) ?

The solution to expand 1/((3n-4a^3)^2) is 1/(9n^2-24a^3n+16a^6)

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expand 1/((3n-4a^3)^2)

expand

\frac{1}{( 3 n - 4 a ^{3} ) ^{2}}

\frac{1}{9 n ^{2} - 24 a ^{3} n + 16 a ^{6}}

Solution steps

\frac{1}{( 3 n - 4 a ^{3} ) ^{2}}

(3 n - 4 a^{3})^{2} = 9 n^{2} - 24 a^{3} n + 16 a^{6}

= \frac{1}{9 n ^{2} - 24 a ^{3} n + 16 a ^{6}}

(cos (5 x) + cos (10 x) + cos (15 x))^{2}

\frac{3 h}{[ ( x + 7 ) ( x + h + 7 ) ]}

2 (62329 - 223)

2 (7^{\frac{1}{12}} - 1)

(5 x^{2} + 5)^{\circ} (2 x + 1)

What is expand 1/((3n-4a^3)^2) ?
The solution to expand 1/((3n-4a^3)^2) is 1/(9n^2-24a^3n+16a^6)