What is expand 7((16pi^2+1)^{3/2}-1) ?

The solution to expand 7((16pi^2+1)^{3/2}-1) is 7(16pi^2+1)^{3/2}-7

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expand 7((16pi^2+1)^{3/2}-1)

expand

7 ((16 π^{2} + 1)^{\frac{3}{2}} - 1)

7 (16 π^{2} + 1)^{\frac{3}{2}} - 7

Solution steps

7 ((16 π^{2} + 1)^{\frac{3}{2}} - 1)

Apply the distributive law:

a (b - c) = ab - a c

a = 7, b = (16 π^{2} + 1)^{\frac{3}{2}}, c = 1

= 7 (16 π^{2} + 1)^{\frac{3}{2}} - 7 \cdot 1

Multiply the numbers:

7 \cdot 1 = 7

= 7 (16 π^{2} + 1)^{\frac{3}{2}} - 7

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What is expand 7((16pi^2+1)^{3/2}-1) ?
The solution to expand 7((16pi^2+1)^{3/2}-1) is 7(16pi^2+1)^{3/2}-7