What is expand (x^{2/3}-x^{1/3})(x^{2/3}+x^{1/3}) ?

The solution to expand (x^{2/3}-x^{1/3})(x^{2/3}+x^{1/3}) is x^{4/3}-x^{2/3}

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expand (x^{2/3}-x^{1/3})(x^{2/3}+x^{1/3})

expand

(x^{\frac{2}{3}} - x^{\frac{1}{3}}) (x^{\frac{2}{3}} + x^{\frac{1}{3}})

x^{\frac{4}{3}} - x^{\frac{2}{3}}

Solution steps

(x^{\frac{2}{3}} - x^{\frac{1}{3}}) (x^{\frac{2}{3}} + x^{\frac{1}{3}})

Apply Difference of Two Squares

(x^{\frac{2}{3}} - x^{\frac{1}{3}}) (x^{\frac{2}{3}} + x^{\frac{1}{3}}) : x^{\frac{4}{3}} - x^{\frac{2}{3}}

= x^{\frac{4}{3}} - x^{\frac{2}{3}}

- \frac{2 x ( 3 y ^{2} - x ^{2} )}{( x ^{2} + y ^{2} )}

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[\frac{k ( k + 1 )}{2}] + (k + 1)

(- 3, 4, - 18) l e f t (k^{3} - k, 0, 1 - k^{2})

16 cos^{4} (2 t) u (t - \frac{π}{4})

What is expand (x^{2/3}-x^{1/3})(x^{2/3}+x^{1/3}) ?
The solution to expand (x^{2/3}-x^{1/3})(x^{2/3}+x^{1/3}) is x^{4/3}-x^{2/3}