What is expand (x-2)(x-3)(x-1+i) ?

The solution to expand (x-2)(x-3)(x-1+i) is (x^3-6x^2+11x-6)+(6+x^2-5x)i

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expand (x-2)(x-3)(x-1+i)

expand

(x - 2) (x - 3) (x - 1 + i)

(x^{3} - 6 x^{2} + 11 x - 6) + (6 + x^{2} - 5 x) i

Solution steps

(x - 2) (x - 3) (x - 1 + i)

Expand

(x - 2) (x - 3) (x - 1 + i) : (x^{2} - 5 x + 6) (x - 1 + i)

= (x^{2} - 5 x + 6) (x - 1 + i)

Distribute parentheses

= x^{2} x + x^{2} (- 1) + x^{2} i - 5 xx - 5 x (- 1) - 5 x i + 6 x + 6 (- 1) + 6 i

Simplify

x^{2} x + x^{2} (- 1) + x^{2} i - 5 xx - 5 x (- 1) - 5 x i + 6 x + 6 (- 1) + 6 i : 6 i + x^{3} - 6 x^{2} + x^{2} i + 11 x - 5 x i - 6

= 6 i + x^{3} - 6 x^{2} + x^{2} i + 11 x - 5 x i - 6

Rewrite in standard complex form:

(x^{3} - 6 x^{2} + 11 x - 6) + (6 + x^{2} - 5 x) i

= (x^{3} - 6 x^{2} + 11 x - 6) + (6 + x^{2} - 5 x) i

co v (α X + b, c Y + d)

(z - 0) (z - 5) (z - (1 - 5))

(x^{\frac{1}{2}})^{2}

e^{10 (t - v)}

2 u^{2} + 2 v^{2} + 4 ((u^{2} + v^{2}))

What is expand (x-2)(x-3)(x-1+i) ?
The solution to expand (x-2)(x-3)(x-1+i) is (x^3-6x^2+11x-6)+(6+x^2-5x)i