What is expand (3e+4)(2h-5)-(e-2)(h+2)+2e+1 ?

The solution to expand (3e+4)(2h-5)-(e-2)(h+2)+2e+1 is 5eh+10h-15e-15

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expand (3e+4)(2h-5)-(e-2)(h+2)+2e+1

expand

(3 e + 4) (2 h - 5) - (e - 2) (h + 2) + 2 e + 1

5 e h + 10 h - 15 e - 15

Solution steps

(3 e + 4) (2 h - 5) - (e - 2) (h + 2) + 2 e + 1

Expand

(3 e + 4) (2 h - 5) : 6 e h - 15 e + 8 h - 20

= 6 e h - 15 e + 8 h - 20 - (e - 2) (h + 2) + 2 e + 1

Expand

- (e - 2) (h + 2) : - e h - 2 e + 2 h + 4

= 6 e h - 15 e + 8 h - 20 - e h - 2 e + 2 h + 4 + 2 e + 1

Simplify

6 e h - 15 e + 8 h - 20 - e h - 2 e + 2 h + 4 + 2 e + 1 : 5 e h + 10 h - 15 e - 15

= 5 e h + 10 h - 15 e - 15

\frac{{ ( - 12 ) + 8 }}{( - 14 )}

(n - 1) + 1

\frac{2 x ^{3} - 1}{x ^{2}}

\frac{d}{d t} ((z (t)) ((t^{3} e^{2 (- 3 + 4 t)})))

What is expand (3e+4)(2h-5)-(e-2)(h+2)+2e+1 ?
The solution to expand (3e+4)(2h-5)-(e-2)(h+2)+2e+1 is 5eh+10h-15e-15