What is expand (2x^3-1)/(x^2) ?

The solution to expand (2x^3-1)/(x^2) is 2x-1/(x^2)

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expand (2x^3-1)/(x^2)

expand

\frac{2 x ^{3} - 1}{x ^{2}}

2 x - \frac{1}{x ^{2}}

Solution steps

\frac{2 x ^{3} - 1}{x ^{2}}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{2 x ^{3} - 1}{x ^{2}} = \frac{2 x ^{3}}{x ^{2}} - \frac{1}{x ^{2}}

= \frac{2 x ^{3}}{x ^{2}} - \frac{1}{x ^{2}}

Cancel

\frac{2 x ^{3}}{x ^{2}} : 2 x

= 2 x - \frac{1}{x ^{2}}

\frac{d}{d t} ((z (t)) ((t^{3} e^{2 (- 3 + 4 t)})))

(2 e^{x} + 3)^{2} e^{x}

{(e^{3 t} + e^{- 3 t}) cos (t)} s

3 (x - 2) - x - 2

cos (x) (2 - 2 sin (x))

What is expand (2x^3-1)/(x^2) ?
The solution to expand (2x^3-1)/(x^2) is 2x-1/(x^2)