What is expand (-0.5)(9-x)(2/3 x-4) ?

The solution to expand (-0.5)(9-x)(2/3 x-4) is -5x+18+(x^2)/3

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expand (-0.5)(9-x)(2/3 x-4)

expand

(- 0.5) (9 - x) (\frac{2}{3} x - 4)

- 5 x + 18 + \frac{x ^{2}}{3}

Solution steps

(- 0.5) (9 - x) (\frac{2}{3} x - 4)

Apply rule:

(- a) = - a

(- 0.5) = - 0.5

= - 0.5 (9 - x) (\frac{2}{3} x - 4)

Apply FOIL method

(9 - x) (\frac{2}{3} x - 4) : 10 x - 36 - \frac{2 x ^{2}}{3}

= - 0.5 (10 x - 36 - \frac{2 x ^{2}}{3})

Apply the distributive law:

m (a + b + c) = ma + mb + m c

- 0.5 (10 x - 36 - \frac{2 x ^{2}}{3}) = - 0.5 \cdot 10 x - 0.5 (- 36) - 0.5 (- \frac{2 x ^{2}}{3})

= - 0.5 \cdot 10 x - 0.5 (- 36) - 0.5 (- \frac{2 x ^{2}}{3})

Simplify

- 0.5 \cdot 10 x - 0.5 (- 36) - 0.5 (- \frac{2 x ^{2}}{3}) : - 5 x + 18 + \frac{x ^{2}}{3}

= - 5 x + 18 + \frac{x ^{2}}{3}

(2 x - 2 x + 4)^{2}

\frac{1}{( x ^{2} + 9 ) ( x - 1 )}

\frac{sin ( π z ^{2} ) + cos ( π z ^{2} )}{( z - 1 ) ( z - 2 )}

(4 cos (t) + 2 sin (t)) (- 2 sin (t) - 3 cos (t))

\frac{( x + 1 ) ^{2}}{x}

What is expand (-0.5)(9-x)(2/3 x-4) ?
The solution to expand (-0.5)(9-x)(2/3 x-4) is -5x+18+(x^2)/3