What is expand 1/((x-5)(x^2-4x+5)) ?

The solution to expand 1/((x-5)(x^2-4x+5)) is 1/(x^3-9x^2+25x-25)

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expand 1/((x-5)(x^2-4x+5))

expand

\frac{1}{( x - 5 ) ( x ^{2} - 4 x + 5 )}

\frac{1}{x ^{3} - 9 x ^{2} + 25 x - 25}

Solution steps

\frac{1}{( x - 5 ) ( x ^{2} - 4 x + 5 )}

Expand

(x - 5) (x^{2} - 4 x + 5) : x^{3} - 9 x^{2} + 25 x - 25

= \frac{1}{x ^{3} - 9 x ^{2} + 25 x - 25}

\frac{( 3 x + 1 ) ^{3}}{6}

(20 3 - 0.4 h - 4 h)^{2}

(t + e^{2 t})^{2}

6 (1 + 43)

4 \cdot (27 x) (- 2 y)

What is expand 1/((x-5)(x^2-4x+5)) ?
The solution to expand 1/((x-5)(x^2-4x+5)) is 1/(x^3-9x^2+25x-25)