What is (\partial)/(\partial x)((m)(y^2-6x^2)) ?

The answer to (\partial)/(\partial x)((m)(y^2-6x^2)) is -12mx

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(\partial)/(\partial x)((m)(y^2-6x^2))

\frac{\partial}{\partial x} ((m) (y^{2} - 6 x^{2}))

- 12 m x

Solution steps

\frac{\partial}{\partial x} ((m) (y^{2} - 6 x^{2}))

Treat

m, y

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= m \frac{\partial}{\partial x} (y^{2} - 6 x^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= m (\frac{\partial}{\partial x} (y^{2}) - \frac{\partial}{\partial x} (6 x^{2}))

\frac{\partial}{\partial x} (y^{2}) = 0

\frac{\partial}{\partial x} (6 x^{2}) = 12 x

= m (0 - 12 x)

Simplify

= - 12 m x

{x^{2} + \frac{1}{2 x}}^{12}

e^{x} (x^{2} - 2 (x - 1))

(x + 3 x) (x - 2 x)

lo g_{5} (125)

\frac{10}{( s + 1 ) ^{2} ( s + 3 )}

What is (\partial)/(\partial x)((m)(y^2-6x^2)) ?
The answer to (\partial)/(\partial x)((m)(y^2-6x^2)) is -12mx