What is expand ((16m^3+n^2)^2)/(16) ?

The solution to expand ((16m^3+n^2)^2)/(16) is 16m^6+2m^3n^2+(n^4)/(16)

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expand ((16m^3+n^2)^2)/(16)

expand

\frac{( 16 m ^{3} + n ^{2} ) ^{2}}{16}

16 m^{6} + 2 m^{3} n^{2} + \frac{n ^{4}}{16}

Solution steps

\frac{( 16 m ^{3} + n ^{2} ) ^{2}}{16}

(16 m^{3} + n^{2})^{2} = 256 m^{6} + 32 m^{3} n^{2} + n^{4}

= \frac{256 m ^{6} + 32 m ^{3} n ^{2} + n ^{4}}{16}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{256 m ^{6} + 32 m ^{3} n ^{2} + n ^{4}}{16} = \frac{256 m ^{6}}{16} + \frac{32 m ^{3} n ^{2}}{16} + \frac{n ^{4}}{16}

= \frac{256 m ^{6}}{16} + \frac{32 m ^{3} n ^{2}}{16} + \frac{n ^{4}}{16}

Divide the numbers:

\frac{256}{16} = 16

= 16 m^{6} + \frac{32 m ^{3} n ^{2}}{16} + \frac{n ^{4}}{16}

Divide the numbers:

\frac{32}{16} = 2

= 16 m^{6} + 2 m^{3} n^{2} + \frac{n ^{4}}{16}

(4 - \frac{1}{n})^{6}

(4 - \frac{1}{n})^{7}

(- 2, - 3) (3 x + 5 y - 12 = 0)

- csc (x) (sin (4 x) - 2 sin (3 x) cos (x))

\frac{12 x ^{3}}{3 x}

What is expand ((16m^3+n^2)^2)/(16) ?
The solution to expand ((16m^3+n^2)^2)/(16) is 16m^6+2m^3n^2+(n^4)/(16)