What is expand-(2e^x)/((e^x+1)(e^x-1))+1 ?

The solution to expand-(2e^x)/((e^x+1)(e^x-1))+1 is -(2e^x)/(e^{2x)-1}+1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand-(2e^x)/((e^x+1)(e^x-1))+1

expand

- \frac{2 e ^{x}}{( e ^{x} + 1 ) ( e ^{x} - 1 )} + 1

- \frac{2 e ^{x}}{e ^{2 x} - 1} + 1

Solution steps

- \frac{2 e ^{x}}{( e ^{x} + 1 ) ( e ^{x} - 1 )} + 1

Expand

(e^{x} + 1) (e^{x} - 1) : e^{2 x} - 1

= - \frac{2 e ^{x}}{e ^{2 x} - 1} + 1

\frac{184 ( s + 5 )}{s ( s + 4 ) ( s ^{2} + 4 )}

\frac{\partial}{\partial x} ((z) (2 x^{3} - 4 x^{2} - 6 y))

\frac{( x - 2 ) ( x + 2 )}{( x - 4 ) ^{2}}

(\frac{1}{3} - x) (1 - x)

(i + k + j) (i + ik + kj + j)^{2}

What is expand-(2e^x)/((e^x+1)(e^x-1))+1 ?
The solution to expand-(2e^x)/((e^x+1)(e^x-1))+1 is -(2e^x)/(e^{2x)-1}+1