What is expand ((6-2x)^2)/9 ?

The solution to expand ((6-2x)^2)/9 is (4x^2)/9-(8x)/3+4

Popular >

expand ((6-2x)^2)/9

expand

\frac{( 6 - 2 x ) ^{2}}{9}

\frac{4 x ^{2}}{9} - \frac{8 x}{3} + 4

Solution steps

\frac{( 6 - 2 x ) ^{2}}{9}

(6 - 2 x)^{2} = 36 - 24 x + 4 x^{2}

= \frac{36 - 24 x + 4 x ^{2}}{9}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{36 - 24 x + 4 x ^{2}}{9} = \frac{36}{9} - \frac{24 x}{9} + \frac{4 x ^{2}}{9}

= \frac{36}{9} - \frac{24 x}{9} + \frac{4 x ^{2}}{9}

Divide the numbers:

\frac{36}{9} = 4

= 4 - \frac{24 x}{9} + \frac{4 x ^{2}}{9}

Cancel

\frac{24 x}{9} : \frac{8 x}{3}

= 4 - \frac{8 x}{3} + \frac{4 x ^{2}}{9}

Rewrite in standard form

= \frac{4 x ^{2}}{9} - \frac{8 x}{3} + 4

(a - 1) (b - 1) (c - 1) (b - a) (c - a) (c - b)

\frac{2 ( 2 - 3 ) + 10}{4}

(- - y + 1 + 3)^{2}

\frac{4 ( - x ^{2} - 16 )}{( x ^{2} - 16 ) ^{2}}

(1 + i 2)^{4}

What is expand ((6-2x)^2)/9 ?
The solution to expand ((6-2x)^2)/9 is (4x^2)/9-(8x)/3+4