What is 5((x^2)/3+2x+4) ?

The solution to 5((x^2)/3+2x+4) is (5(x^2+6x+12))/3

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simplify 5((x^2)/3+2x+4)

simplify

5 (\frac{x ^{2}}{3} + 2 x + 4)

\frac{5 ( x ^{2} + 6 x + 12 )}{3}

Solution steps

5 (\frac{x ^{2}}{3} + 2 x + 4)

Join

\frac{x ^{2}}{3} + 2 x + 4 : \frac{x ^{2} + 6 x + 12}{3}

= 5 \cdot \frac{x ^{2} + 6 x + 12}{3}

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{5 ( x ^{2} + 6 x + 12 )}{3}

- (2 x + 1) sin (x^{2} + x)

4 (4 x + \frac{1}{x})

\frac{2 ( x - 8 )}{( x - 5 ) ^{2}}

\frac{5 ( 6 - x ) ^{2}}{3}

R (- 3, 2, - 5) S (- 5, 1, - 3)