What is expand (2x)left(3x+2) ?

The solution to expand (2x)left(3x+2) is 6elx^2ft+4elxft

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expand (2x)left(3x+2)

expand

(2 x) l e f t (3 x + 2)

6 e l x^{2} f t + 4 e l x f t

Solution steps

(2 x) l e f t (3 x + 2)

= e l f t (2 x) (3 x + 2)

Apply the distributive law:

a (b + c) = ab + a c

a = (2 x) l e f t, b = 3 x, c = 2

= (2 x) l e f t \cdot 3 x + (2 x) l e f t \cdot 2

= 3 e l x f t (2 x) + 2 e l f t (2 x)

Simplify

3 e l x f t (2 x) + 2 e l f t (2 x) : 6 e l x^{2} f t + 4 e l x f t

= 6 e l x^{2} f t + 4 e l x f t

ρ (y_{t - 1} = β x_{t - 1} + u_{t - 1} (ρ, y, t, x))

\frac{1 - e ^{- 2 x}}{( x ) ( x ^{2} + 2 x + 5 )}

\frac{2 ( n - 2 E ) ^{2}}{n ^{2}}

(2 x y^{2} + \frac{x}{y ^{2}}) d x

a^{a^{a} (a + 1)}

What is expand (2x)left(3x+2) ?
The solution to expand (2x)left(3x+2) is 6elx^2ft+4elxft