What is the d/(dt)((x)(2+0.05t)) ?

The d/(dt)((x)(2+0.05t)) is (dx)/(dt)(2+0.05t)+0.05x

What is the first d/(dt)((x)(2+0.05t)) ?

The first d/(dt)((x)(2+0.05t)) is (dx)/(dt)(2+0.05t)+0.05x

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\frac{d}{d t} ((x) (2 + 0.05 t))

\frac{d x}{d t} (2 + 0.05 t) + 0.05 x

Solution steps

\frac{d}{d t} ((x) (2 + 0.05 t))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x, g = 2 + 0.05 t

= \frac{d x}{d t} (2 + 0.05 t) + \frac{d}{d t} (2 + 0.05 t) x

\frac{d}{d t} (2 + 0.05 t) = 0.05

= \frac{d x}{d t} (2 + 0.05 t) + 0.05 x

(\frac{5 y - 3}{2})^{2}

sin^{2} (x) (cot (x) - csc (x))

\frac{13}{2} (e^{3 t} - e^{- 3 t})

(sec (x) + tan (x)) co x - 1

(\frac{5 ^{- 3}}{5 ^{- 5}})^{2}

What is the d/(dt)((x)(2+0.05t)) ?
The d/(dt)((x)(2+0.05t)) is (dx)/(dt)(2+0.05t)+0.05x
What is the first d/(dt)((x)(2+0.05t)) ?
The first d/(dt)((x)(2+0.05t)) is (dx)/(dt)(2+0.05t)+0.05x