What is expand (50-q/2 = 9/4 300-4p)(75-q/4) ?

The solution to expand (50-q/2 = 9/4 300-4p)(75-q/4) is 3750-13q=(675q)/4-300p+qp

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expand (50-q/2 = 9/4 300-4p)(75-q/4)

expand

(50 - \frac{q}{2} = \frac{9}{4} 300 - 4 p) (75 - \frac{q}{4})

3750 - 13 q = \frac{675 q}{4} - 300 p + qp

Solution steps

(50 - \frac{q}{2} = \frac{9}{4} \cdot 300 - 4 p) (75 - \frac{q}{4})

= (50 - 300 \cdot \frac{9}{4} = \frac{q}{2} - 4 p) (75 - \frac{q}{4})

Distribute parentheses

= 50 \cdot 75 + 50 (- \frac{q}{4}) + (- \frac{q}{2} = \frac{9}{4} \cdot 300) \cdot 75 + (- \frac{q}{2} = \frac{9}{4} \cdot 300) (- \frac{q}{4}) + (- 4 p) \cdot 75 + (- 4 p) (- \frac{q}{4})

Apply minus-plus rules

+ (- a) = - a, (- a) (- b) = ab

50 \cdot 75 - 50 \cdot \frac{q}{4} - \frac{q}{2} = 300 \cdot 75 \cdot \frac{9}{4} + \frac{q}{2} = 300 \cdot \frac{9}{4} \cdot \frac{q}{4} - 4 \cdot 75 p + 4 \cdot \frac{q}{4} p

Simplify

50 \cdot 75 - 50 \cdot \frac{q}{4} - \frac{q}{2} = 300 \cdot 75 \cdot \frac{9}{4} + \frac{q}{2} = 300 \cdot \frac{9}{4} \cdot \frac{q}{4} - 4 \cdot 75 p + 4 \cdot \frac{q}{4} p : 3750 - 13 q = \frac{675 q}{4} - 300 p + qp

3750 - 13 q = \frac{675 q}{4} - 300 p + qp

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What is expand (50-q/2 = 9/4 300-4p)(75-q/4) ?
The solution to expand (50-q/2 = 9/4 300-4p)(75-q/4) is 3750-13q=(675q)/4-300p+qp