What is expand ((x+2)(x-1))/((x-3)(x+4)) ?

The solution to expand ((x+2)(x-1))/((x-3)(x+4)) is (x^2+x-2)/(x^2+x-12)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand ((x+2)(x-1))/((x-3)(x+4))

expand

\frac{( x + 2 ) ( x - 1 )}{( x - 3 ) ( x + 4 )}

\frac{x ^{2} + x - 2}{x ^{2} + x - 12}

Solution steps

\frac{( x + 2 ) ( x - 1 )}{( x - 3 ) ( x + 4 )}

Expand

(x - 3) (x + 4) : x^{2} + x - 12

= \frac{( x + 2 ) ( x - 1 )}{x ^{2} + x - 12}

Expand

(x + 2) (x - 1) : x^{2} + x - 2

= \frac{x ^{2} + x - 2}{x ^{2} + x - 12}

5 (3 - 2)

\frac{( z ^{2} + 1 ) ^{2}}{( z - i ) ^{2}}

2 sin (3) (x - 180) - 1

d x - (x^{3} e^{y} + \frac{x ( 2 y - 5 )}{2 ( y ^{2} - 5 y + 6 )}) d y

(x - \frac{5}{3}) \cdot (x - \frac{7}{3})

What is expand ((x+2)(x-1))/((x-3)(x+4)) ?
The solution to expand ((x+2)(x-1))/((x-3)(x+4)) is (x^2+x-2)/(x^2+x-12)