What is ((2m)/3+7b)((2m)/3-7b) ?

The solution to ((2m)/3+7b)((2m)/3-7b) is ((21b+2m)(-21b+2m))/9

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simplify ((2m)/3+7b)((2m)/3-7b)

simplify

(\frac{2 m}{3} + 7 b) (\frac{2 m}{3} - 7 b)

\frac{( 21 b + 2 m ) ( - 21 b + 2 m )}{9}

Solution steps

(\frac{2 m}{3} + 7 b) (\frac{2 m}{3} - 7 b)

Join

\frac{2 m}{3} + 7 b : \frac{21 b + 2 m}{3}

= \frac{21 b + 2 m}{3} (\frac{2 m}{3} - 7 b)

Join

\frac{2 m}{3} - 7 b : \frac{- 21 b + 2 m}{3}

= \frac{21 b + 2 m}{3} \cdot \frac{- 21 b + 2 m}{3}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{( 21 b + 2 m ) ( - 21 b + 2 m )}{3 \cdot 3}

Multiply the numbers:

3 \cdot 3 = 9

= \frac{( 21 b + 2 m ) ( - 21 b + 2 m )}{9}

(x + \frac{1}{2}) (x + \frac{11}{2})

\frac{90 ( s + 0.3 )}{( s + 3.8 ) ( s - 2.9 ) ( s + 10 )}

\frac{1}{s ( s ^{2} + 2 s + 10 )}

- \frac{4 ( 72 - 5 P ^{2} )}{3}

\frac{k ( s + 2 ) ( s + 1 )}{( s - 2 ) ( s - 1 )}

What is ((2m)/3+7b)((2m)/3-7b) ?
The solution to ((2m)/3+7b)((2m)/3-7b) is ((21b+2m)(-21b+2m))/9